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  • Arrange the following orbitals in decreasing order of energy. A. n = 3, l = 0, m = 0 B. n = 4, l = 0, m = 0 C. n = 3, l = 1, m = 0 D. n = 3, l = 2, m = 1

Arrange the following orbitals in decreasing order of energy.

A. n = 3, l = 0, m = 0

B. n = 4, l = 0, m = 0

C. n = 3, l = 1, m = 0

D. n = 3, l = 2, m = 1

The correct option for the order is :

Option: 1

D > B > C > A


Option: 2

D > B > A > C


Option: 3

A > C > B > D


Option: 4

B > D > C > A


Answers (1)

best_answer

According to (n+l) rule Orbital has more value of (n+l) has more energy. If value of some then orbital has more value of n has more energy

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sudhir.kumar

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