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Assertion : A P-N photodiode is made from a semiconductor for which Eg = 2.8 eV. This photo diode will not detect the wavelength of 6000 nm.

Reason : A PN photodiode detect wavelength l if  \frac{h c}{\lambda}>E_{g}

Option: 1

both assertion and reason are true and the reason is the correct explanation of the assertion.


Option: 2

both assertion and reason are true but the reason is not the correct explanation of the assertion.


Option: 3

assertion is true but reason is false.


Option: 4

the assertion and reason both are false.


Answers (1)

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\begin{array}{l}{\text { For detection of a particular wavelength }(\lambda) \text { by a } P N \text { photo diode, energy of incident light }>E_{g} \Rightarrow \frac{h c}{E_{g}}>\lambda} \\ {\text { For }} \\ {E_{g}=2.8 e V, \frac{h c}{E_{g}}=\frac{6.6 \times 10^{-34} \times 3 \times 10^{8}}{2.8 \times 1.6 \times 10^{-19}}=441.9 n m} \\ {\text { i.e., } \frac{h c}{E_{q}}<6000 n m, \text { so diode will not detect the wavelength of } 6000 \mathrm{A} \text { . }}\end{array}

 

 

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Divya Prakash Singh

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