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Assume carbon burns according to following equation :

2 \mathrm{C}_{(\mathrm{s})}+\mathrm{O}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{CO}(\mathrm{g})  When 12 g carbon is burnt in 48 g of oxygen, the volume of carbon monoxide produced is \times 10^{-1}\text{L} STP [nearest integer]

[Given: Assume co as ideal gas, Mass of c is 12 g mol–1, Mass of O is 16 g mol–1 and molar volume of an ideal gas STP is 22.7 L mol–1]

Option: 1

227


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & 2 \mathrm{C}+\mathrm{O}_2 \rightarrow 2 \mathrm{CO} \\ \\& 12 \mathrm{~g} \quad 48 \mathrm{gm} \\ \\& 1 \mathrm{~mole} 1.5 \text { mole } \\ & \text { "C" is } \mathrm{LR} \text {. } \\ & \text { Moles of } \mathrm{CO} \text { formed }=1 \\ & \text { Volume of } \mathrm{CO}=1 \times 22.7 \\ & =227 \times 10^{-1} \mathrm{~L} \end{aligned}

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Devendra Khairwa

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