At room temperature, a dilute solution of urea is prepared by dissolving 0.60g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mmHg, lowering of vapour pressure(in mmHg) will be: (molar mass of urea = 60g/mol)
Option: 1 0.017
Option: 2 0.028
Option: 3 0.027
Option: 4 0.031
Molecular weight of urea = 60 g / mol
Now, we know that :
Relative lowering of vapour pressure is equal to the molar mass of the solute.
option (1) is correct.
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