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Then which body will have greater time of flight ???

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For projectile on horizontal ground

time of flight is given by 

T_1 = \frac{2Usin\theta}{g }

For projectile on an inclined plane

time of flight is given by 

T_2 = \frac{2Usin\theta}{gcos\beta}

So T_2 > T_1 (except \ \beta =90^0)

Where  \beta = Angle of inclination

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avinash.dongre

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