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Calculate the heat required to raise the temperature of 100 g of water from \mathrm{25^{\circ} \mathrm{C}} to its boiling point at
\mathrm{100^{\circ} \mathrm{C}}. The specific heat capacity of water is \mathrm{4.18 \mathrm{~J} /\left(\mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right)}

Option: 1

31350 J


Option: 2

21359 J


Option: 3

23467 J


Option: 4

42000 J


Answers (1)

best_answer

The heat (Q) required to change the temperature of a substance can be calculated using the formula:

\mathrm{Q=m \cdot c \cdot \Delta T}

Where: Q = Heat (in joules) m = Mass of the substance (in grams) c = Specific heat capacity \mathrm{\left(4.18 \mathrm{~J} /\left(\mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right)\right) \Delta T=\text { Change in temperature }\left(\text { in }{ }^{\circ} \mathrm{C}\right)}
Step 1: Identify the given values: - m (mass) = 100 g - c (specific heat capacity) =\mathrm{4.18 \mathrm{~J} /\left(\mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right)} - ?T (change in temperature) = (100C − 25C) = 75C
Step 2: Apply the formula to calculate the heat required:

\mathrm{\begin{gathered} Q=100 \mathrm{~g} \cdot 4.18 \mathrm{~J} /\left(\mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right) \cdot 75 \mathrm{C} \\ Q=31,350 \mathrm{~J} \end{gathered}}

So, the heat required to raise the temperature of 100 g of water from \mathrm{25^{\circ} \mathrm{C}} to its boiling point at \mathrm{100^{\circ} \mathrm{C}} is 31, 350 joules.
So, correct option is A

Posted by

Divya Prakash Singh

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