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Calculate the wavelength (in nanometre) associated with a proton moving at 1.0 x 103 ms-1.
(Mass of proton = 1.67 × 10-27kg and h = 6.63 × 10-34 Js)

Option: 1

0.032 \: nm


Option: 2

0.40\: nm


Option: 3

2.5 \: nm


Option: 4

14.0 \: nm


Answers (1)

best_answer

As we learnt in 

De-broglie wavelength -

\lambda = \frac{h}{mv}= \frac{h}{p}

- wherein

where m is the mass of the particle

v its velocity 

p its momentum

 

 \lambda = \frac{h}{mv} = \frac{{6.63} \times {10^{-34}}} {{1.67} \times {10^{-27}} \times {10^3}}

        =0.40 nm

Therefore, Option(2) is correct

Posted by

Sanket Gandhi

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