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A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 x 10-6 J/T when a magnetic intensity of 60 x 103 A/m is applied. Its magnetic susceptibility is :

  • Option 1)

    3.3 x 10-2

  • Option 2)

    3.3 x 10-4

  • Option 3)

    4.3 x 10-2

  • Option 4)

    2.3 x 10-2

Answers (1)

best_answer

 

Magnetic Susceptibility -

\chi _{m}= \frac{I}{H}

- wherein

Intensity of magnetisation - I

Magnetic intensity - H

 

Magnetic Moment =20\times 10^{-6}  J/T

volume = a^{3}=10^{-6}m^{3}

I=\frac{Magnetic moment }{volume}=\frac{20\times 10^{-6}}{10^{-6}}=20N/m^{2}

H=60\times 10^{3}A/m

& susceptibility =x = \frac{I}{H}=\frac{20}{60\times 10^{3}}

x=3.3\times 10^{-4}

 

 


Option 1)

3.3 x 10-2

Option 2)

3.3 x 10-4

Option 3)

4.3 x 10-2

Option 4)

2.3 x 10-2

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