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At a certain distance from a point charge the electric field is 500Vm  and the potential is 3000V . What is this distance

  • Option 1)

    6m

  • Option 2)

    12m

  • Option 3)

    36m

  • Option 4)

    144m

 

Answers (2)

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As we learned

 

Relation between E and V in integral form -

\dpi{100} dV=-\int_{r_{1}}^{r_{2}}\overrightarrow{E}\cdot \vec{d}r=-\int_{r_{1}}^{r_{2}}Edr\cos \theta

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 V=E\times r\Rightarrow r=\frac{V}{E}=\frac{3000}{500}=6m


Option 1)

6m

Option 2)

12m

Option 3)

36m

Option 4)

144m

Posted by

Avinash

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Option 1

Posted by

Shivangi

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