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Three particles, each having a charge of 10C are placed at the corners of an equilateral triangle of side 10cm. The electrostatic potential energy of the system is (Given \frac{1}{4\pi\epsilon_0} = 9\times 10^9)

  • Option 1)

    Zero

  • Option 2)

    Infinite

  • Option 3)

    27 J

  • Option 4)

    100 J

 

Answers (1)

best_answer

As we have learnt,

 

Potential Energy Of System Of two Charge -

U=\frac{kQ_{1}Q_{2}}{r}  \left ( S.I \right )

U= \frac{Q_{1}Q_{2}}{r}  \left ( C.G.S \right ) 

 

- wherein

K=\frac{1}{4\pi \epsilon _{0}}

 

 Potential Energy of the system,

U = 9\times 10^9\left[\frac{(10\times 10^{-6})^2}{0.1}\times 3\right ] = 27 J

 


Option 1)

Zero

Option 2)

Infinite

Option 3)

27 J

Option 4)

100 J

Posted by

Aadil

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