Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Can someone explain Equal masses of methane and oxygen are mixed in an empty container at 25°C. The fraction of the total pressure exerted by oxygen is

Equal masses of methane and oxygen are mixed in an empty container at 25°C. The fraction of the total pressure exerted by oxygen is

  • Option 1)

    1/2

  • Option 2)

    2/3

  • Option 3)

    1/3\times \frac{273}{298}

  • Option 4)

    1/3

 

Answers (2)

best_answer

As we learnt in

Partial Pressure of a gas in gaseous mixture -

Partial Pressure = (Total Pressure of Mixture) \times (mole fraction of gas)

 

-

 

 

 

Let the mass of methane and oxygen be m gm

Mole\: fraction \: of\: oxygen,\: x_{O_{2}}

= \frac{\frac{m}{32}}{\frac{m}{32}+\frac{m}{16}}= \frac{m}{32}\times \frac{32}{3m}= \frac{1}{3}

Let the total pressure be  P

\therefore partial\: pressure\: of\: O_{2},p_{o_{2}}= P\times x_{O_{2}}

                                                                = P\times \frac{1}{3}= \frac{1}{3}P

Correct option is 4.


Option 1)

1/2

This is an incorrect option.

Option 2)

2/3

This is an incorrect option.

Option 3)

1/3\times \frac{273}{298}

This is an incorrect option.

Option 4)

1/3

This is the correct option.

Posted by

divya.saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Engineering aspirant dies by suicide in Kota, fourth case this year
anam-khan

What is non-Aadhaar declaration in JEE Main 2025? Explain mismatch between image, face
anam-khan

Forgot JEE Main password 2025 for downloading admit card? Here’s what to do

Latest Question