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If \overrightarrow{P}.\overrightarrow{Q}=PQ, then angle between \overrightarrow{P} and \overrightarrow{Q} is

  • Option 1)

    0\degree

  • Option 2)

    30\degree

  • Option 3)

    45\degree

  • Option 4)

    60\degree

 

Answers (1)

best_answer

As learnt in

Scalar , Dot or Inner Product -

Scalar product of two vector \vec{A} & \vec{B} written as \vec{A} \cdot \vec{B} is a scalar quantity given by the product of magnitude of \vec{A} & \vec{B} and the cosine of smaller angle between them.

\vec{A}\cdot \vec{B}= A\, B\cdot \cos \Theta

- wherein

showing representation of scalar products of vectors.

 

 \vec{P}\cdot \vec{Q} = PQ = PQ\cos \Theta = PQ

\cos \Theta = 1 = \cos \Theta = \cos 0^{\circ}

\therefore \Theta = 0^{\circ}


Option 1)

0\degree

This option is correct

Option 2)

30\degree

This option is incorrect

Option 3)

45\degree

This option is incorrect

Option 4)

60\degree

This option is incorrect

Posted by

Aadil

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