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To neutralise completely 20 ml of 0.1 M aqueous solution of phosphorous acid \left ( H_{3} PO_{3}\right ) the volume of 0.1 M aqueous KOHsolution required is

  • Option 1)

    10 mL

  • Option 2)

    20 mL

  • Option 3)

    40 mL

  • Option 4)

    60 mL.

 

Answers (1)

best_answer

As we learnt in

Molarity -

Molarity = \frac{Moles \: of \: solute}{V\! ol.of\: solution(L)}

-

 

 

 

H_{3}PO_{3}\: is \: a\: dibasic\: acid.\:

Miliequivalent of acid = Miliequivalent of base

N_{1}V_{1}\left ( acid \right )= N_{2}V_{2}\left ( acid \right )

0.1\times 2\times 20= 0.1\times 1\times V_{2}

V_{2}= \frac{0.1\times 2\times 20}{0.1\times 1}= 40\: mL

Correct option is 3.


Option 1)

10 mL

This is in correct option.

Option 2)

20 mL

This is in correct option.

Option 3)

40 mL

This is the correct option.

Option 4)

60 mL.

This is in correct option.

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