Two waves of intensities I and 4I superpose, then the maximum and minimum intensities produced are:

  • Option 1)

    5I and 3I

  • Option 2)

    9I and I

  • Option 3)

    9I and 3I

  • Option 4)

    5I and I

 

Answers (1)

 

Maximum amplitude & Intensity -

When \theta = 0,2\pi ---2n\pi
 

- wherein

A_{max }= A_{1}+A_{2}

I_{max }= \left ( \sqrt{I_{1}}+\sqrt{I_{2}} \right )^{2}

 

 

Minimum amplitude & Intensity -

\theta = \left ( 2n+1 \right )\pi
 

- wherein

A_{min }= A_{1}-A_{2}

I_{min }= \left ( \sqrt{I_{1}}-\sqrt{I_{2}} \right )^{2}

 

 I_{max} = \left ( \sqrt{I_{1}} \right+\sqrt{I_{2}} )^{2} =\left ( \sqrt{I} \right+\sqrt{4I} )^{2} = 9I

I_{min} = \left ( \sqrt{I_{1}} \right-\sqrt{I_{2}} )^{2} =\left ( \sqrt{I} \right-\sqrt{4I} )^{2} = I


Option 1)

5I and 3I

Incorrect

Option 2)

9I and I

Correct

Option 3)

9I and 3I

Incorrect

Option 4)

5I and I

Incorrect

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