Get Answers to all your Questions

header-bg qa

A magnet of total magnetic moment 10^{-2}\hat{i}  A-m^{2} is placed in a time-varying magnetic field, B\hat{i}(coswt) where B=1 Tesla and w=0.125 rad/s. The work done for reversing the direction of the magnetic moment at t=1 second, is: 

  • Option 1)

    0.01 J

  • Option 2)

    0.007 J

     

  • Option 3)

    0.028 J

  • Option 4)

    0.014 J

Answers (1)

best_answer

 

Work done in rotating a bar magnet -

W= MB\left ( 1-\cos \Theta \right )

W=2MB\; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \;\; \; \; \; \; \; \; \; M=10^{-2}\widehat{l}A-m^{2}

=2\times 10^{-2}\times 1\times \cos (0.125)\; \; \; \; \; \; \; \; \; \; \; B= B\: \widehat{l}\cos wt

W=2\times 10^{-2}\times 1\times \cos (0.125)\; \; \; \; \; \; \; \; \; \; \; w= 0.125 \: rad/s

w \approx 0.02 J\; \; \; \; \; \; \; \; \; \; \; \; \; \; \; B = I \; Tesla

Or W\approx 0.014 J

 

-W\approx 0.02 J\\\\OR \: \: \: W\approx0.014J

 

 

 


Option 1)

0.01 J

Option 2)

0.007 J

 

Option 3)

0.028 J

Option 4)

0.014 J

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE