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  • Can someone help me with this, A particle of mass ‘m’ and charge ‘q’ is accelerated through a potential difference of V volt, its energy will be

A particle of mass ‘m’ and charge ‘q’ is accelerated through a potential difference of V volt, its energy will be

  • Option 1)

    qV

  • Option 2)

    mqV

  • Option 3)

    \left(\frac{q}{m} \right )V

  • Option 4)

    \frac{q}{mV}

 

Answers (1)

As we have learnt,

 

Electron Volt -

It is the smallest practical unit of energy if used in atomic and nuclear Physics.

 

 

 

- wherein

1\, e v= 1.6\times 10^{-19}J

1.6\times 10^{-12}erg.

 

  KE = qV

 


Option 1)

qV

Option 2)

mqV

Option 3)

\left(\frac{q}{m} \right )V

Option 4)

\frac{q}{mV}

Posted by

Vakul

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