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Can someone help me with this, A prism can produce a minimum deviation d in a light beam. If three such prisms are combined, the minimum deviation that can be produced in this beam is:

A prism can produce a minimum deviation d in a light beam. If three such prisms are combined, the minimum deviation that can be produced in this beam is:

  • Option 1)

    0

  • Option 2)

    d

  • Option 3)

    2d

  • Option 4)

    3d

 
Answers (1)
221 Views

 

Condition of maximum deviation -

i=e

 

 

- wherein

\delta _{min}= 2i-A

\mu = \frac{\sin \left ( \frac{\delta _{m}+A}{2} \right )}{\sin \left ( A/2 \right )}

 

  value of a minimum deviation

d_{net} = d-d+d =d


Option 1)

0

Incorrect

Option 2)

d

Correct

Option 3)

2d

Incorrect

Option 4)

3d

Incorrect

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