A simple harmonic motion having an amplitude A and time period T is represented by the equation y = 5 sin p (t + 4)m then the values of (A in m) and (T in  sec) are

  • Option 1)

    A = 5, T = 2

  • Option 2)

    A = 10, T = 1

  • Option 3)

    A = 5, T = 1

  • Option 4)

    A = 10, T = 2

 

Answers (1)

As we discussed in concept

Phase -

The quantity \phi = wt+\delta is called the phase . It determines the status of the particle in simple harmonic motion.

 

 

- wherein

e.g. 

x= A\sin \left ( wt +\delta \right )\rightarrow phase

 

 y=5\: sin p (\pi t + 4)

w=\frac{2\pi }{T}

T=\frac{2\pi }{w}=\frac{2\pi }{\pi }

T=2 sec

A=5

 


Option 1)

A = 5, T = 2

Option is correct

Option 2)

A = 10, T = 1

Option is incorrect

Option 3)

A = 5, T = 1

Option is incorrect

Option 4)

A = 10, T = 2

Option is incorrect

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