A vessel at 1000 K contains CO2 with a pressure of 0.5 atm. Some of the CO2 is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is

  • Option 1)

    1.8 atm

  • Option 2)

    3 atm

  • Option 3)

    0.3 atm

  • Option 4)

    0.18 atm

 

Answers (1)

As we learnt in

Equilibrium constant in gaseous system -

For equilibrium involving gases, it is usually more convenient to express the equilibrium constant in terms of partial pressure. 

- wherein

The ideal gas equation is written as 

PV=nRT

 

 

                                           CO_{2}_{(g)}+C_{(s)}\leftrightharpoons 2CO_{(g)}

Initial pressure                     0.5 atm         0                  0

Pressure at equilibrium       0.5-x                              2x

Total Pressure =  0.5 - x + 2x = 0.8

x = 0.3

k = \frac{(pco^{2})}{\left ( pco_{2} \right )}

k = \frac{(0.6)^{2}}{0.2}

=1.8 atm

 


Option 1)

1.8 atm

This is correct.

Option 2)

3 atm

This is incorrect.

Option 3)

0.3 atm

This is incorrect.

Option 4)

0.18 atm

This is incorrect.

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