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  • Can someone help me with this, - Electrostatics - JEE Main-6

A charged ball B hangs from a silk thread S, which makes an angle \theta with a large charged conducting sheet P, as shown in the figure. The surface charge density \sigma of the sheet is proportional to

                    

 

 

  • Option 1)

    \sin \theta

     

     

     

  • Option 2)

    \tan \theta

  • Option 3)

    \cos \theta

  • Option 4)

    \cot \theta

 

Answers (1)

best_answer

As we learned

 

infinite thin plate sheet of charge -

E=\frac{\sigma }{2\epsilon _{0}}\left ( E\propto r^{0} \right )

V=\frac{\sigma r }{2\epsilon _{0}}+c

- wherein

 

 

 T\sin \theta =qE

T\cos \theta =mg

\Rightarrow \tan \theta =\frac{qE}{mg}=\frac{q}{mg}\left ( \frac{\sigma }{2\varepsilon _{0}} \right )

\Rightarrow \sigma \alpha \tan \theta .


Option 1)

\sin \theta

 

 

 

Option 2)

\tan \theta

Option 3)

\cos \theta

Option 4)

\cot \theta

Posted by

Plabita

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