Knockout JEE Main April 2021 (One Month)
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18 g of glucose is added to 178.2 g of water. The vapour pressure of water for this aqueous solution at
is
759.00 torr
7.60 torr
76.00 torr
752.40 torr.
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As we learnt in
Expression of relative lowering of vapour pressure -
- wherein
Mole fraction of glucose
ps = Vapour pressure of solution = 752.4 torr.
Correct option is 4.
Option 1)
759.00 torr
This is an incorrect option.
Option 2)
7.60 torr
This is an incorrect option.
Option 3)
76.00 torr
This is an incorrect option.
Option 4)
752.40 torr.
This is the correct option.