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  • Can someone help me with this, The plates of parallel plate capacitor are charged upto 100 V. A 2 mmthick plate is inserted between the plates. Then to maintain the same potential difference, the distance between the plates is increased by1.6mm. The

The plates of parallel plate capacitor are charged upto 100 V  . A 2 mm thick plate is inserted between the plates. Then to maintain the same potential difference, the distance between the plates is increased by1.6mm  . The dielectric constant of the plate is

  • Option 1)

    5

  • Option 2)

    1.25

  • Option 3)

    4

  • Option 4)

    2.5

 

Answers (1)

best_answer

As we have learned

If dielectric insert between the sphere -

{C}'=4\pi \epsilon _{0}k\frac{ab}{b-a}

-

 

 

In air the potential difference between the plates

 

              V_{air}= \frac{\sigma }{\varepsilon _0}.....(1)                   

In the presence of partially filled medium potential difference between the plates

V_{m}= \frac{\sigma }{\varepsilon _0}\left ( d-t+t/k \right )....(2)           

Potential difference between the plates with dielectric medium and increased distance is

V_{m'}= \frac{\sigma }{\varepsilon _0}\left ( (d+d')-t+t/k \right )....(3)  

According to question V_{air}= V'_m  which givesK= \frac{t}{t-d'}

Hence K= \frac{2}{2-1.6}=5

 

 


Option 1)

5

Option 2)

1.25

Option 3)

4

Option 4)

2.5

Posted by

Himanshu

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