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Clark's method involves the formation of : 

Option: 1

carbonate salts 


Option: 2

bicarbonate salts 


Option: 3

chloride salts 


Option: 4

sulphide salts 


Answers (1)

best_answer

As we have learned

Clark's Method -

In this method, temporary hardness is removed by adding Slaked Lime Ca(OH)2

Ca(HCO_3)_2 + Ca(OH)_2 \rightarrow 2CaCO_3 + 2 H_2O

Carbonate salts precipitate easily and thus temporary hardness can be removed by Clark's method.

Therefore, option(1) is correct.

Posted by

Rishabh

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