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  • Confused! kindly explain, An engine pumps water continously through a hose. Water leaves the hose with velocity V and m is the mass per unit length of the water jet. What is the rate at whoch kinetic energy is imparted to water?

An engine pumps water continously through a hose. Water leaves the hose with velocity V and m is the mass per unit length of the water jet. What is the rate at whoch kinetic energy is imparted to water?

  • Option 1)

    mV^{2}

  • Option 2)

    \frac{1}{2}\: mV^{2}

  • Option 3)

    \frac{1}{2}m^{2}V^{2}

  • Option 4)

    \frac{1}{2}mV^{3}

 

Answers (1)

best_answer

As discussed in

Kinetic energy -

k= frac{1}{2}mv^{2}

- wherein

m ightarrow mass

v ightarrow velocity

kinetic Energy is never negative

 

 m - mass per unit length

\therefore rate of mass leaving the hose per second = \frac{mx}{t} = mv

Rate of k \acute{c} = \frac{1}{2} (mv).v^{2}=\frac{1}{2}mv^{3}


Option 1)

mV^{2}

This solution is incorrect

Option 2)

\frac{1}{2}\: mV^{2}

This solution is incorrect

Option 3)

\frac{1}{2}m^{2}V^{2}

This solution is incorrect

Option 4)

\frac{1}{2}mV^{3}

This solution is correct

Posted by

divya.saini

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