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  • Confused! kindly explain, Experimentally it was found that a metal oxide has formula M0.98O.Metal M, is present as M2+and M3+ in its oxide. Fraction of the metal which exists as M3+ would be:

Experimentally it was found that a metal oxide has formula M0.98O.Metal M, is present as M2+and  M3+ in its oxide. Fraction of the metal which exists as M3+  would be:

  • Option 1)

    5.08 %

  • Option 2)

    7.01 %

  • Option 3)

    4.08 %

  • Option 4)

    6.05 %

 

Answers (1)

best_answer

As we have learned

Oxidation Number -

Oxidation number denotes the oxidation state of an element in a compound ascertained according to a set of rules formulated on the basis that electron pair in a covalent bond belogs entirely to more electronegative elements.

-

 

 3x + 2 (0.98 -x) = 2 

 x+ 1.96 = 2 

x  = 0.04 

% of M^{3+} = \frac{0.04}{0.98} \times 100 = 4.08 \%

 


Option 1)

5.08 %

Option 2)

7.01 %

Option 3)

4.08 %

Option 4)

6.05 %

Posted by

SudhirSol

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