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In XeF_{2},\; XeF_{4},\; XeF_{6}, the number of lone pairs on Xe are respectively

  • Option 1)

    2, 3, 1

  • Option 2)

    1, 2, 3

  • Option 3)

    4, 1, 2

  • Option 4)

    3, 2, 1

 

Answers (1)

best_answer

As learnt in

Structure of Xenon hexafluoride -

Distorted octahedral and hybridisation is Sp3d3

- wherein

 

 

Xe2F2 has sp3 d2 hybridisation and total number of valance electrons of Xe=8, two electrons are shared with 21 atoms and 6 are left in 3 lone pairs. 

Similarly, Xe2F4 has sp3 d2 hybridisation, 4 electrons or shared in bonds and 4 are left in 2 lone pairs and X2F6 and sp3 d3 hybridisation, 6 electrons are shared in bonds and 2 are lone pair.

Xe has 8 valence electrons

XeF6 : 6 bond pairs,    1 lone pair

XeF4 : 4 bond pairs,    2 lone pairs

XeF2 : 2 bond pairs,    3 lone pairs


Option 1)

2, 3, 1

This option is incorrect

Option 2)

1, 2, 3

This option is incorrect

Option 3)

4, 1, 2

This option is incorrect

Option 4)

3, 2, 1

This option is correct

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