Q

# Confused! kindly explain, - Optics - JEE Main-4

In a double slit experiment, when a thin film of thickness t having refractive index $\mu$ is introduced in front of one of the slits, the maximum at the centre of the fringe pattern shifts by one fringe width. The value of t is ( $\lambda$ is the wavelenth of the light used) :

• Option 1)

$\frac{\lambda}{2(\mu-1)}$

• Option 2)

$\frac{2\lambda}{(\mu-1)}$

• Option 3)

$\frac{\lambda}{(2\mu-1)}$

• Option 4)

$\frac{\lambda}{(\mu-1)}$

Views

In YDSE

$\triangle X=(\mu-1)\frac{tD}{d}=\beta = \frac{\lambda D}{d}$

$\Rightarrow t=\frac{\lambda}{(\mu-1)}$

Option 1)

$\frac{\lambda}{2(\mu-1)}$

Option 2)

$\frac{2\lambda}{(\mu-1)}$

Option 3)

$\frac{\lambda}{(2\mu-1)}$

Option 4)

$\frac{\lambda}{(\mu-1)}$

Exams
Articles
Questions