In a double slit experiment, when a thin film of thickness t having refractive index \mu is introduced in front of one of the slits, the maximum at the centre of the fringe pattern shifts by one fringe width. The value of t is ( \lambda is the wavelenth of the light used) :

  • Option 1)

    \frac{\lambda}{2(\mu-1)}

  • Option 2)

    \frac{2\lambda}{(\mu-1)}

  • Option 3)

    \frac{\lambda}{(2\mu-1)}

  • Option 4)

    \frac{\lambda}{(\mu-1)}

 

Answers (1)

In YDSE

\triangle X=(\mu-1)\frac{tD}{d}=\beta = \frac{\lambda D}{d}

\Rightarrow t=\frac{\lambda}{(\mu-1)}


Option 1)

\frac{\lambda}{2(\mu-1)}

Option 2)

\frac{2\lambda}{(\mu-1)}

Option 3)

\frac{\lambda}{(2\mu-1)}

Option 4)

\frac{\lambda}{(\mu-1)}

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