Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Confused! kindly explain, Radius of the second Bohr orbit of a singly ionised helium atom is

Radius of the second Bohr orbit of a singly ionised helium atom is

  • Option 1)

    0.53 A \degree

  • Option 2)

    1.06 A \degree

  • Option 3)

    0.265 A \degree

  • Option 4)

    0.132 A \degree

 

Answers (1)

best_answer

As we learned in concept

Radius of nth orbital -

r_{n}= \frac{\epsilon _{0}n^{2}h^{2}}{\pi mZe^{2}}

 

- wherein

r_{n}\alpha \: \frac{n^{2}}{Z}

\frac{\epsilon_{0}h^{2}}{\pi me^{2}}= 0.529A^{\circ}

 

 R = R_{o}\frac{n^{2}}{Z}

n=2 and Z=2

\therefore R-R_{o}\:.\:\frac{4}{2}=2R_{o}=1.06A^{\circ} (Since R_{O}=0.53A^{\circ})


Option 1)

0.53 A \degree

Option 2)

1.06 A \degree

Option 3)

0.265 A \degree

Option 4)

0.132 A \degree

Posted by

prateek

View full answer

Similar Questions

Trending Articles/News

anam-khan

BITS Pilani begins direct admission process 2025 for board exam toppers; eligibility, tie-breaking rule
anam-khan

BITSAT 2025 session 1 absentee slot registration begins; exam on June 2
anam-khan

BITSAT 2025 May 30 Exam LIVE: Day 5 shift 2 exam ends; paper analysis, difficulty level, updates

Latest Question