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  • Confused! kindly explain, - Three charges +Q, q, +Q are placed respectively, at distance,0,d/2 and d from the origin, on the . I - Electrostatics - JEE Main

Three charges +Q, q, +Q are placed respectively, at distance,0,d/2 and d from the origin, on the x-axis. If the net force experienced by +Q. placed at x=0, is zero, then value of q is :

  • Option 1)

    -Q/4\:

  • Option 2)

    \: +Q/2\:

  • Option 3)

    \: +Q/4\:

  • Option 4)

    \: -Q/2

Answers (1)

best_answer

 

Coulombic force -

F\propto Q_{1}Q_{2}=F\propto \frac{Q_{1}Q_{2}}{r^{2}}=F=\frac{KQ_{1}Q_{2}}{r^{2}}

- wherein

K - proportionality Constant 

Q1 and Q2 are two Point charge

given F on Q at 0 = zero

\therefore \frac{KQq}{\left ( \frac{d}{2} \right )^{2}} + \frac{kQ^{2}}{d^{2}} = 0

4 q = - Q

q = \frac{-Q}{4}


Option 1)

-Q/4\:

Option 2)

\: +Q/2\:

Option 3)

\: +Q/4\:

Option 4)

\: -Q/2

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