what is the 2015th term of a sequence of natural numbers written in accending order, that does not have any perfect squares.

  • Option 1)

    2058

  • Option 2)

    2059

  • Option 3)

    2060

  • Option 4)

    2062

 

Answers (1)
V Vakul

As learnt in

Sequence -

Arragement of real numbers specified in a definite order, by some assigned law.

- wherein

Notations -

a_{1},a_{2},a_{3},a_{4}.........a_{n}

or

< a_{n}>

 

 

We get,

 

\sqrt{2015}\approx 44.8

Thus total terms are 2015+44.8\approx 2059.8

 i.e., 2060


Option 1)

2058

This option is incorrect.

Option 2)

2059

This option is incorrect.

Option 3)

2060

This option is correct.

Option 4)

2062

This option is incorrect.

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