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Consider an imaginary ion \mathrm{{ }_{22}^{48} \mathrm{X}^{3-}}. The nucleus contains \mathrm{\text { ' } a ' \%} more neutrons than the number of electrons in the ion. The value of \mathrm{\text { ' } a \text { ' }} is __________. [ nearest integer]

Option: 1

4


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{_{22}^{48}\textrm{X}^{3-}} , Mass number = 48 (Prontons+neutrons)

               Atomic number = 22 (Protons)

              Total number of electron = 22+3

                                                     = 25

Now, neutrons = 48-22=26

So, 1 neutron is more in number than electrons.

So,

\mathrm{a% = \frac{1}{25}\times 100=4}

Answer = 4

Posted by

Pankaj Sanodiya

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