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  • Consider the above reaction where 6.1g of Benzoic acid is used to get 7.8g of m-Bromo benzoic acid. The percentage yield of the produc

Consider the above reaction where 6.1g of Benzoic acid is used to get 7.8g of m-Bromo benzoic acid. The percentage yield of the product is ________. (Rounded off to the nearest integer) [Given: Atomic masses : C: 120.0u, H: 1.0 u, O : 16.0 u, Br : 80.0 u ]
 

Answers (1)

best_answer

Given,

Now,

\frac{\text { moles of } \mathrm{PhCOOH}}{1}=\frac{\text { Moles of } \mathrm{C}_{6} \mathrm{H}_{4} \mathrm{COOHBr}}{1}

\text { Moles of } \mathrm{C}_{6} \mathrm{H}_{4} \mathrm{COOHBr}=\frac{6.1}{122}=\frac{1}{20} \mathrm{~mol}

Hence,

Mass = molar mass X mole 

\text { mass of } \mathrm{C}_{6} \mathrm{H}_{4} \mathrm{COOHBr}=201 \times \frac{1}{20} \mathrm{gm}

Now,

\% \text { yield }=\frac{\text { Actual weight }}{\text { Theoretical weight }} \times 100\% \text { yield }=\frac{7.8}{10.05} \times 100

\% \text { yield }=77.61 \%

Ans = 78

Posted by

Kuldeep Maurya

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