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Consider the following conversion:

The order in which the following reagents have to be used to carry out the given conversion is :

$\mathrm{(i)\ CH_3Cl/AlCl_3}$

$\mathrm{(ii)\ KMnO_4,H^+}$

$\mathrm{(iii)\ \Delta}$

$\mathrm{(iv)\ conc.\ HNO_3,conc.\ H_2SO_4}$
Option: 1
$\mathrm{(i),(ii), (iii),(iv)}$

Option: 2
$\mathrm{(iv),(i), (ii),(iii)}$

Option: 3
$\mathrm{(i),(ii), (iv),(iii)}$

Option: 4
$\mathrm{(i),(iv), (ii),(iii)}$

Answers (1)

The reaction will be -

Therefore, the correct option is (4)

Posted by

Sumit Saini

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