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  • Consider the situation as shown in figure. The point  is the centre. The light ray forms an angle

Consider the situation as shown in figure. The point \mathrm{O} is the centre. The light ray forms an angle of \mathrm{60^{\circ}} with the normal. The normal makes an angle \mathrm{60^{\circ}} with the horizontal and the mirror makes an angle \mathrm{60^{\circ}} with the normal. The value of refractive index of that spherical portions, so that light ray retraces its path is:

Option: 1

\sqrt{2}


Option: 2

\frac{2}{\sqrt{3}}


Option: 3

\frac{3}{2}


Option: 4

\mathrm{\sqrt{3}}


Answers (1)

best_answer


Refractive index, \mu=\frac{\sin 60^{\circ}}{\sin 30^{\circ}}=\frac{\sqrt{3} / 2}{1 / 2}=\sqrt{3}

Posted by

rishi.raj

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