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Considered the graphs of  \mathrm{y=A x^2 \text { and } y^2+3=x^2+4 y} , where A is

a positive constant and \mathrm{x, y \in R} . The number of points in which 

the two graphs intersect is

Option: 1

98


Option: 2

88


Option: 3

94


Option: 4

96


Answers (1)

best_answer

Transverse axis is the equation of the angle bisector 

containing point (2,3) , which is given by

\mathrm{\begin{aligned} & \frac{3 x-4 y+5}{\sqrt{3^2+4^2}}=\frac{12 x+5 y-40}{\sqrt{12^2+5^2}} \\ & 21 x+77 y=265 \quad \therefore \quad a+b=98 \end{aligned}}

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SANGALDEEP SINGH

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