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- Determine the frequency of revolution of the electron in 3rd Bohr's orbit in hydrogen atom:Option: 1 0.024 x 1016Hz</di
Determine the frequency of revolution of the electron in 3rd Bohr's orbit in hydrogen atom:
0.024 x 1016Hz
3.4 x 1016Hz
8.13 x 1016Hz
0.054 x 1016Hz
Answers (1)
As we have learnt,
Frequency = 1/(Time period)
Time period = Total distance covered/velocity
= 2πr/v
Thus, frequency = v/2πr
Now, velocity of electron in 3rd Bohr’s orbit = 2.16 x 106(1/3)m/s
= 0.72 x 106m/s
And, radius of 3rd Bohr’s orbit = 0.53 x 10-10(32/1)
= 4.77 x 10-10m
Now, frequency = v/2πr
= 0.72 x 106m/s / (2 x 3.14 x 4.77 x 10-10m)
= 0.024 x 1016Hz
Therefore, Option(1) is correct
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