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Dimensions of specific resistance is
Option: 1
$\left [ ML^{3}T^{-3}A^{+2} \right ]$

Option: 2
$\left [ ML^{-3}T^{3}A^{-2} \right ]$

Option: 3
$\left [ ML^{3}T^{-3}A^{-2} \right ]$

Option: 4
$\left [ MLT^{-3}A^{-2} \right ]$

Answers (1)

As we learnt

Unit and Dimension -

Ohm.mt - S.I Unit

$ML^{3}T^{-3}A^{-2}\rightarrow$ Dimensions

- wherein

specific resistance

$\rho = \frac{RA}{L}$

$[\rho] = \frac{[ML^2T^{-3}A^{-2}][L^2]}{[L]}$

$= [ML^3T^{-2}A^{-2}]$

Posted by

Kshitij

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