Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Displacement of a particle as function of time is given as  .

Displacement of a particle as function of time is given as  s=at^{3}+bt^{2}+c . Then its acceleration as function of time is (a)

Option: 1

Independent  of  time


Option: 2

a is linear function of time


Option: 3

a is quadratic function of time


Option: 4

a = 0


Answers (1)

best_answer

As we learned

 Some important Formulas of differentiation

  • \frac{d}{dx}\left ( x^{n} \right )={n} x^{n-1}

 So using the formula 

 \\*a=\frac{dV}{dt}\\*\\*V=\frac{ds}{dt}=\frac{d}{dt}\left [ at^{3}+bt^{2}+c \right ]=3at^{^{2}}+2bt\\*\\*\Rightarrow a=\frac{d}{dt}\left ( 3at^{2}+2bt \right )=6at+2b

a is a linear function of time

 

Posted by

Riya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question