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Eight chairs are numbered 1 to 8 . Two women and three men wish to occupy one chair each. First the women choose the chairs from amongst the chairs marked 1 to 4 ; and then the men select the chairs from the remaining. The number of possible arrangements is

Option: 1

{ }^6 C_3 \times{ }^4 C_2


Option: 2

{ }^4 P_2 \times{ }^6 P_3


Option: 3

{ }^4 C_2 \times{ }^4 P_3


Option: 4

{ }^4 P_2 \times{ }^6 P_3 \times 3!


Answers (1)

best_answer

Women can sit in { }^4 P_2 ways. Then on remaining 6 chairs, 3 men will sit in { }^6 P_3 ways.

So number of arrangements ={ }^4 P_2 \times{ }^6 P_3

 

Posted by

Pankaj Sanodiya

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