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  • Electrons are accelerated through a potential difference V and protons are accelerated through a potential diffrence 4 V. The de-broglie wavelengths are <img alt="\lambda _{e}" src="https://le

Electrons are accelerated through a potential difference V and protons are accelerated through a potential diffrence 4 V. The de-broglie wavelengths are \lambda _{e} and \lambda _{p} for electrons and protons respectively. The ratio of \frac{\lambda _{e}}{\lambda _{p}} is given by : (given me is mass of electron and mp is mass of proton).

Option: 1

\frac{\lambda _{e}}{\lambda _{p}}=\sqrt{\frac{m_{p}}{m_{e}}}


Option: 2

\frac{\lambda _{e}}{\lambda _{p}}=\sqrt{\frac{m_{e}}{m_{p}}}


Option: 3

\frac{\lambda _{e}}{\lambda _{p}}=\frac{1}{2}\sqrt{\frac{m_{e}}{m_{p}}}


Option: 4

\frac{\lambda _{e}}{\lambda _{p}}=2\sqrt{\frac{m_{p}}{m_{e}}}


Answers (1)

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\frac{\lambda_{e}}{\lambda_{p}}=\frac{\sqrt{2 m_{p} k_{p}}}{\sqrt{2 m_{e} k_{e}}}=\frac{\sqrt{2 \times m_{p} \times e \times 4 v}}{\sqrt{2 \times m_{e} \times e \times v}} \Rightarrow \frac{\lambda_{e}}{\lambda_{p}}=2 \sqrt{\frac{m_{p}}{m_{e}}}

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shivangi.shekhar

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