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  • Figure shows two coherent sources S1, S2 vibrating in same phase. AB is an irregular wire lying at a far distance from the sources S1 and S2. Let <img al

Figure shows two coherent sources S1, S2 vibrating in same phase. AB is an irregular wire lying at a far distance from the sources S1 and S2. Let \frac{\lambda }{d} = 10^{-3}. \angle BOA = 0.12^{0}. How many bright spots will be seen on the wire, including points A and B.

Option: 1

2


Option: 2

3


Option: 3

4


Option: 4

more than 4


Answers (1)

best_answer

 

Fringe Width -

\beta = \frac{\lambda D}{d}
 

- wherein

\beta = y_{n+1}-y_{n}

y_{n+1}= Distance of\left ( n+1 \right )^{th}

Maxima= \left ( n+1 \right )\frac{\lambda D}{d}

y_{n}=Distance of n^{th}

 maxima = \frac{n\lambda D}{d}

 

 

Say ‘n’ fringes are present in the region shown by ‘y’

\Rightarrow y = n\beta = \frac{n. \lambda D}{d}

\Rightarrow \frac{y}{D}\approx \tan (0.06^{0})\approx \frac{0.06 \times \pi}{180} = \frac{n \lambda }{d}

n = \frac{10^{3}\times \pi}{180}\times 0.06= \frac{\pi }{3}>1

Hence; only one maxima above and below point O. So total 3 bright spots will be present (including point ‘O’ i.e. the central maxima).

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