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Find the equation to the tangent of circle $x^2 + y^2 = 26$ at the point (5,1)
Option: 1
x + 5y = 26

Option: 2
5x + y = 26

Option: 3
$x +5y = \sqrt {26 }$

Option: 4
$5x +y = \sqrt {26 }$

Answers (1)

best_answer

Here x₁ = 5, y₁= 1

So equation of tangent to given circle at (5,1) is

xx₁+ yy₁= 26

Thus ,we get $5x + y = 26$

Posted by

Ajit Kumar Dubey

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