Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Find the equation to the tangent of circle  at the point (5,1)&nbsp

Find the equation to the tangent of circle x^2 + y^2 = 26 at the point (5,1) 

Option: 1

x + 5y = 26 


Option: 2

5x + y = 26 


Option: 3

x +5y = \sqrt {26 }


Option: 4

5x +y = \sqrt {26 }


Answers (1)

best_answer

Here x1 = 5, y1 = 1

So equation of tangent to given circle at (5,1) is

xx1 + yy1 = 26

Thus ,we get  5x + y = 26

Posted by

Ajit Kumar Dubey

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2026 Registration LIVE: NTA session 1 application dates soon; exam, registration fee updates
anam-khan

JEE Mains 2026 Registration LIVE: NTA JEE session 1 application, exam dates soon; city choice available
anam-khan

JEE Main 2026 exam city option not removed: NTA dismisses viral claim

Latest Question