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  • Find the number of solutions of <img alt="\left[\left(\frac{10 \times 10}{20}\right)(a+b)\right]=20" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cleft%5B%5Cleft%28%5Cfrac%7B10%20%5C

Find the number of solutions of \left[\left(\frac{10 \times 10}{20}\right)(a+b)\right]=20 ,  such that m and n are odd numbers

Option: 1

1


Option: 2

3


Option: 3

9


Option: 4

2


Answers (1)

best_answer

Given,
\begin{aligned} & {\left[\left(\frac{10 \times 10}{20}\right)(a+b)\right]=20 \text { and }} \\ & a, b>0 \end{aligned}
Generalized formula to find the number of solutions of equations is

a_1+a_2+\ldots . .+a_r=(n+r-1) c_{r-1} Let, $a=4 a$ and $b=4 b Then, $a+b=4So the equation becomes
a + b = 1
Hence from above equation, n = 1 and r = 2
Hence the total number of solutions =(1+2-1) c_{2-1}=2 c_1=2

Posted by

manish painkra

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