For a measurement of the radius of a ball following readings are taken:
3.26cm 3.28cm 3.31cm
Absolute error for the first reading is?
Given readings-
$$
Mean = \frac {3.26 + 3.28 + 3.31}{3}= \frac {9.85} {3}= 3.283cm
$$ $$
Absolute error=|Mean−Reading|= |3.283−3.26|=0.023cm
$$
Hence, the absolute error for the first reading (3.26 cm) is 0.023 cm.
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