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  • For a reaction  1.0 mol of X 1.5mol of Y and 0.5mol of Z were taken in a 1L vessel and allowed to react. At equilibriu

For a reaction X+Y\rightleftharpoons Z 1.0 mol of X 1.5mol of Y and 0.5mol of Z were taken in a 1L vessel and allowed to react. At equilibrium, concentration of Z was 1mol/L . The equilibrium constant of reaction is  x/16. What is x?
Option: 1 16
Option: 2 -
Option: 3 -
Option: 4 -

Answers (1)

best_answer

The reaction occurs as follows:

                \mathrm{X\: +\: Y\: \rightleftharpoons 2Z}

t = 0            1          1.5        0.5
t = teq      (1-x)    (1.5-x)    (0.5 + 2x)

Given, 0.5 + 2x = 1

Thus, x = 0.25

Now, Keq is given as:

\mathrm{K_{eq}\: =\: \frac{1^{2}}{(1.25)(0.75)}\: =\: \frac{16}{15}}

Hence, x = 16.

Posted by

Kuldeep Maurya

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