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For a reaction, a catalyst decreases activation energy from 93.314\: \text{to} \: 85 \mathrm{~kJ} \mathrm{~mol}^{-1}$ at $400 \mathrm{~K}. What will be the rate of reaction as compared to uncatalyzed rx^{n}? Assume other parameters equal.

Option: 1

7.38


Option: 2

12.2


Option: 3

21.4


Option: 4

73.8


Answers (1)

best_answer

\mathrm{k_{1}=A e^{-\frac{93.314 \times 1000}{8.314 \times 400}}}

\mathrm{k_{2}=A e^{-\frac{85 \times 1000}{8.314 \times 400}}}

\mathrm{\frac{k_{2}}{k_{1}}=\exp \left(\frac{8.314 \times 1000}{8.314 \times 400}\right)=\exp (2.5) }

\mathrm{k_{2}=12.2\, k_{1}}

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