Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • For a real gas at temperature and high pressure ( 99 bar) the value of compressibility factor is 2, so

For a real gas at 25^{\circ} \mathrm{C} temperature and high pressure ( 99 bar) the value of compressibility factor is 2, so the value of Vander Waal's constant \mathrm{' b '} should be_____________ \times 10^{-2} \mathrm{~L} \mathrm{~mol}^{-1}(Nearest integer)
(Given \mathrm{R}=0.083 \mathrm{~L}$ bar $\mathrm{K}^{-1} \mathrm{~mol}^{-1})

Option: 1

25


Option: 2

-


Option: 3

--


Option: 4

-


Answers (1)

best_answer

we know, at high pressure the compressibility factor will be -

\mathrm{ z=1+\frac{P b}{R T} \Rightarrow 2=1+\frac{99 \times b}{0.083 \times 298}}
\mathrm{ 2=1+\left(\frac{99}{0.083 \times 298}\right)^{b} }
\mathrm{b=\frac{0.083 \times 298}{99}=0.249}
\mathrm{b=25\times 10^{-2}\, L\, mol^{-1}}

Ans = 25.

Posted by

Riya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question