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 For the given first order reaction A \rightarrow B the half life of the reaction is 0.65/9 \mathrm{~min} the ratio of the initial concentration of reactant to the concentration of reactant at time 3.0min will be equal to {Round of to Next integer}

Option: 1

10^7


Option: 2

10^8


Option: 3

10^{1.4}


Option: 4

10^{15}


Answers (1)

best_answer

\mathrm{\begin{aligned} & k=\frac{2.303}{t} \log \left[\frac{A_0}{A_t}\right] \\ & \frac{0.693}{t \frac{1}{2}}=\frac{2.303}{t} \log \left(\frac{A_0}{A_t}\right) \\ & \frac{0.693}{0.6519 \min }=\frac{2.303}{3 \min } \log \left(\frac{A_0}{A_t}\right) \\ & \log \left(\frac{A_0}{A_t}\right)=\frac{0.693 \times 3}{2.303 \times 0.6519} \\ & \frac{A_0}{A_t}=10^{1.4} \end{aligned} }

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vishal kumar

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