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For the reaction, \mathrm{SO_{2(g)}+\frac{1}{2}O_{2(g)}\rightleftharpoons SO_{3(g)}}  if \mathrm{K_P=K_C(RT)^x} where the symbols have usual meaning then the value of x is 

Option: 1

-1


Option: 2

-\\frac{1}{2}


Option: 3

\\frac{1}{2}


Option: 4

1


Answers (1)

As we discussed in the concept

Relation between Kp and Kc -

\mathrm{K_{p}=K_{c}(RT)^{\Delta n}}

According to the data given in the question

\mathrm{K_{C}(RT)^{\Delta n}=K_C(RT)^{x}}

For the given reaction

\mathrm{SO_{2}(g)+\frac{1}{2}O_{2}(g)\rightleftharpoons SO_{3}(g)}

\mathrm{\Delta n=1-\frac{3}{2}=-\frac{1}{2}}

\text{Hence, the value of x is } -\frac{1}{2}

Therefore, the correct answer is Option (2)

Posted by

Ramraj Saini

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