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For the Reaction R \rightarrow P. data are tabulated below

\begin{array}{ccccc} \text { Time }(\min ) & 0 & 5 & 15 & 35 \\ \mathrm{\frac{1}{[R]}\left(M^{-1}\right)} & 1 & 2 & 4 & 8 \end{array}

Determine the order of the reaction

 

Option: 1

1


Option: 2

2


Option: 3

3


Option: 4

4


Answers (1)

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As \mathrm{ \frac{1}{[R]}} is tabulated, so assume second order reaction,

\begin{aligned} &\mathrm{ k=\frac{1}{t}\left[\frac{1}{a-x}-\frac{1}{a}\right] }\\ &\mathrm{ k=\frac{1}{5}[2-1]=\frac{1}{5} M^{-1} \min ^{-1} }\\ &\mathrm{ k=\frac{1}{15}[4-1]=\frac{1}{5} M^{-1} \min ^{-1} }\\ &\mathrm{ k=\frac{1}{35}[8-1]=\frac{1}{5} M^{-1} \min ^{-1}}\\ \end{aligned}

So, order =2

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chirag

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